7(1+4x)5=-8(1-4x)

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Solution for 7(1+4x)5=-8(1-4x) equation: 



7(1+4x)5=-8(1-4x)

We move all terms to the left:

7(1+4x)5-(-8(1-4x))=0

We add all the numbers together, and all the variables

7(4x+1)5-(-8(-4x+1))=0

We multiply parentheses

140x-(-8(-4x+1))+35=0



We calculate terms in parentheses: -(-8(-4x+1)), so:

-8(-4x+1)

We multiply parentheses

32x-8

Back to the equation:

-(32x-8)



We get rid of parentheses

140x-32x+8+35=0

We add all the numbers together, and all the variables

108x+43=0

We move all terms containing x to the left, all other terms to the right

108x=-43

x=-43/108

x=-43/108

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