7(1+4n)=7(6+3n)

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Solution for 7(1+4n)=7(6+3n) equation: 



7(1+4n)=7(6+3n)

We move all terms to the left:

7(1+4n)-(7(6+3n))=0

We add all the numbers together, and all the variables

7(4n+1)-(7(3n+6))=0

We multiply parentheses

28n-(7(3n+6))+7=0



We calculate terms in parentheses: -(7(3n+6)), so:

7(3n+6)

We multiply parentheses

21n+42

Back to the equation:

-(21n+42)



We get rid of parentheses

28n-21n-42+7=0

We add all the numbers together, and all the variables

7n-35=0

We move all terms containing n to the left, all other terms to the right

7n=35

n=35/7

n=5

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