7(1+3x)+8=-3(4x-4)+3

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Solution for 7(1+3x)+8=-3(4x-4)+3 equation: 



7(1+3x)+8=-3(4x-4)+3

We move all terms to the left:

7(1+3x)+8-(-3(4x-4)+3)=0

We add all the numbers together, and all the variables

7(3x+1)-(-3(4x-4)+3)+8=0

We multiply parentheses

21x-(-3(4x-4)+3)+7+8=0



We calculate terms in parentheses: -(-3(4x-4)+3), so:

-3(4x-4)+3

We multiply parentheses

-12x+12+3

We add all the numbers together, and all the variables

-12x+15

Back to the equation:

-(-12x+15)



We add all the numbers together, and all the variables

21x-(-12x+15)+15=0

We get rid of parentheses

21x+12x-15+15=0

We add all the numbers together, and all the variables

33x=0

x=0/33

x=0

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