7(-7+2b)=5(b-7)-5b

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Solution for 7(-7+2b)=5(b-7)-5b equation: 



7(-7+2b)=5(b-7)-5b

We move all terms to the left:

7(-7+2b)-(5(b-7)-5b)=0

We add all the numbers together, and all the variables

7(2b-7)-(5(b-7)-5b)=0

We multiply parentheses

14b-(5(b-7)-5b)-49=0



We calculate terms in parentheses: -(5(b-7)-5b), so:

5(b-7)-5b

We add all the numbers together, and all the variables

-5b+5(b-7)

We multiply parentheses

-5b+5b-35

We add all the numbers together, and all the variables

-35

Back to the equation:

-(-35)



We add all the numbers together, and all the variables

14b-14=0

We move all terms containing b to the left, all other terms to the right

14b=14

b=14/14

b=1

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