7(-6x-2)+368=2(-2x-10)-348

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Solution for 7(-6x-2)+368=2(-2x-10)-348 equation: 



7(-6x-2)+368=2(-2x-10)-348

We move all terms to the left:

7(-6x-2)+368-(2(-2x-10)-348)=0

We multiply parentheses

-42x-(2(-2x-10)-348)-14+368=0



We calculate terms in parentheses: -(2(-2x-10)-348), so:

2(-2x-10)-348

We multiply parentheses

-4x-20-348

We add all the numbers together, and all the variables

-4x-368

Back to the equation:

-(-4x-368)



We add all the numbers together, and all the variables

-42x-(-4x-368)+354=0

We get rid of parentheses

-42x+4x+368+354=0

We add all the numbers together, and all the variables

-38x+722=0

We move all terms containing x to the left, all other terms to the right

-38x=-722

x=-722/-38

x=+19

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