7(-5y-3)-8=2(-3y-5)-3(5+7y)

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Solution for 7(-5y-3)-8=2(-3y-5)-3(5+7y) equation: 



7(-5y-3)-8=2(-3y-5)-3(5+7y)

We move all terms to the left:

7(-5y-3)-8-(2(-3y-5)-3(5+7y))=0

We add all the numbers together, and all the variables

7(-5y-3)-(2(-3y-5)-3(7y+5))-8=0

We multiply parentheses

-35y-(2(-3y-5)-3(7y+5))-21-8=0



We calculate terms in parentheses: -(2(-3y-5)-3(7y+5)), so:

2(-3y-5)-3(7y+5)

We multiply parentheses

-6y-21y-10-15

We add all the numbers together, and all the variables

-27y-25

Back to the equation:

-(-27y-25)



We add all the numbers together, and all the variables

-35y-(-27y-25)-29=0

We get rid of parentheses

-35y+27y+25-29=0

We add all the numbers together, and all the variables

-8y-4=0

We move all terms containing y to the left, all other terms to the right

-8y=4

y=4/-8

y=-1/2

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