7(-2v-4)=5v-4(7v-11)

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Solution for 7(-2v-4)=5v-4(7v-11) equation:



7(-2v-4)=5v-4(7v-11)
We move all terms to the left:
7(-2v-4)-(5v-4(7v-11))=0
We multiply parentheses
-14v-(5v-4(7v-11))-28=0
We calculate terms in parentheses: -(5v-4(7v-11)), so:
5v-4(7v-11)
We multiply parentheses
5v-28v+44
We add all the numbers together, and all the variables
-23v+44
Back to the equation:
-(-23v+44)
We get rid of parentheses
-14v+23v-44-28=0
We add all the numbers together, and all the variables
9v-72=0
We move all terms containing v to the left, all other terms to the right
9v=72
v=72/9
v=8

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