7(-2-c)=16+3c

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Solution for 7(-2-c)=16+3c equation: 



7(-2-c)=16+3c

We move all terms to the left:

7(-2-c)-(16+3c)=0

We add all the numbers together, and all the variables

7(-1c-2)-(3c+16)=0

We multiply parentheses

-7c-(3c+16)-14=0

We get rid of parentheses

-7c-3c-16-14=0

We add all the numbers together, and all the variables

-10c-30=0

We move all terms containing c to the left, all other terms to the right

-10c=30

c=30/-10

c=-3

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