6z=5z2

Solution for 6z=5z2 equation:

6z=5z^2

We move all terms to the left:

6z-(5z^2)=0

determiningTheFunctionDomain
-5z^2+6z=0

a = -5; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-5)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-5}=\frac{-12}{-10}
=1+1/5
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-5}=\frac{0}{-10}
=0
$