6z-36-2z=6(z-9)B

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Solution for 6z-36-2z=6(z-9)B equation: 



6z-36-2z=6(z-9)

We move all terms to the left:

6z-36-2z-(6(z-9))=0

We add all the numbers together, and all the variables

4z-(6(z-9))-36=0



We calculate terms in parentheses: -(6(z-9)), so:

6(z-9)

We multiply parentheses

6z-54

Back to the equation:

-(6z-54)



We get rid of parentheses

4z-6z+54-36=0

We add all the numbers together, and all the variables

-2z+18=0

We move all terms containing z to the left, all other terms to the right

-2z=-18

z=-18/-2

z=+9

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