6z+1=2(3z-1)

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Solution for 6z+1=2(3z-1) equation: 



6z+1=2(3z-1)

We move all terms to the left:

6z+1-(2(3z-1))=0



We calculate terms in parentheses: -(2(3z-1)), so:

2(3z-1)

We multiply parentheses

6z-2

Back to the equation:

-(6z-2)



We get rid of parentheses

6z-6z+2+1=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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