6y-7+2(5y+1)=-2(y+1)

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Solution for 6y-7+2(5y+1)=-2(y+1) equation: 



6y-7+2(5y+1)=-2(y+1)

We move all terms to the left:

6y-7+2(5y+1)-(-2(y+1))=0

We multiply parentheses

6y+10y-(-2(y+1))+2-7=0



We calculate terms in parentheses: -(-2(y+1)), so:

-2(y+1)

We multiply parentheses

-2y-2

Back to the equation:

-(-2y-2)



We add all the numbers together, and all the variables

16y-(-2y-2)-5=0

We get rid of parentheses

16y+2y+2-5=0

We add all the numbers together, and all the variables

18y-3=0

We move all terms containing y to the left, all other terms to the right

18y=3

y=3/18

y=1/6

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