6y-4=2(3y-2)

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Solution for 6y-4=2(3y-2) equation: 



6y-4=2(3y-2)

We move all terms to the left:

6y-4-(2(3y-2))=0



We calculate terms in parentheses: -(2(3y-2)), so:

2(3y-2)

We multiply parentheses

6y-4

Back to the equation:

-(6y-4)



We get rid of parentheses

6y-6y+4-4=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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