6y-2(y+1)=3(y-2)+2

Solution for 6y-2(y+1)=3(y-2)+2 equation:

6y-2(y+1)=3(y-2)+2

We move all terms to the left:

6y-2(y+1)-(3(y-2)+2)=0

We multiply parentheses

6y-2y-(3(y-2)+2)-2=0


We calculate terms in parentheses: -(3(y-2)+2), so:

3(y-2)+2

We multiply parentheses

3y-6+2

We add all the numbers together, and all the variables

3y-4

Back to the equation:

-(3y-4)


We add all the numbers together, and all the variables

4y-(3y-4)-2=0

We get rid of parentheses

4y-3y+4-2=0

We add all the numbers together, and all the variables

y+2=0

We move all terms containing y to the left, all other terms to the right

y=-2