6y-(3y+y)=17

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Solution for 6y-(3y+y)=17 equation: 



6y-(3y+y)=17

We move all terms to the left:

6y-(3y+y)-(17)=0

We add all the numbers together, and all the variables

6y-(+4y)-17=0

We get rid of parentheses

6y-4y-17=0

We add all the numbers together, and all the variables

2y-17=0

We move all terms containing y to the left, all other terms to the right

2y=17

y=17/2

y=8+1/2

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