6y+42=-6(y-1)

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Solution for 6y+42=-6(y-1) equation: 



6y+42=-6(y-1)

We move all terms to the left:

6y+42-(-6(y-1))=0



We calculate terms in parentheses: -(-6(y-1)), so:

-6(y-1)

We multiply parentheses

-6y+6

Back to the equation:

-(-6y+6)



We get rid of parentheses

6y+6y-6+42=0

We add all the numbers together, and all the variables

12y+36=0

We move all terms containing y to the left, all other terms to the right

12y=-36

y=-36/12

y=-3

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