6y+3(y-5)=(y+1)-4

Solution for 6y+3(y-5)=(y+1)-4 equation:

6y+3(y-5)=(y+1)-4

We move all terms to the left:

6y+3(y-5)-((y+1)-4)=0

We multiply parentheses

6y+3y-((y+1)-4)-15=0


We calculate terms in parentheses: -((y+1)-4), so:

(y+1)-4

We get rid of parentheses

y+1-4

We add all the numbers together, and all the variables

y-3

Back to the equation:

-(y-3)


We add all the numbers together, and all the variables

9y-(y-3)-15=0

We get rid of parentheses

9y-y+3-15=0

We add all the numbers together, and all the variables

8y-12=0

We move all terms containing y to the left, all other terms to the right

8y=12

y=12/8

y=1+1/2