6y+28=(4y+16)

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Solution for 6y+28=(4y+16) equation: 



6y+28=(4y+16)

We move all terms to the left:

6y+28-((4y+16))=0



We calculate terms in parentheses: -((4y+16)), so:

(4y+16)

We get rid of parentheses

4y+16

Back to the equation:

-(4y+16)



We get rid of parentheses

6y-4y-16+28=0

We add all the numbers together, and all the variables

2y+12=0

We move all terms containing y to the left, all other terms to the right

2y=-12

y=-12/2

y=-6

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