6y+1=2(y+4)+5

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Solution for 6y+1=2(y+4)+5 equation: 



6y+1=2(y+4)+5

We move all terms to the left:

6y+1-(2(y+4)+5)=0



We calculate terms in parentheses: -(2(y+4)+5), so:

2(y+4)+5

We multiply parentheses

2y+8+5

We add all the numbers together, and all the variables

2y+13

Back to the equation:

-(2y+13)



We get rid of parentheses

6y-2y-13+1=0

We add all the numbers together, and all the variables

4y-12=0

We move all terms containing y to the left, all other terms to the right

4y=12

y=12/4

y=3

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