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6y(4y=9)=0
We move all terms to the left:
6y(4y-(9))=0
We multiply parentheses
24y^2-54y=0
a = 24; b = -54; c = 0;
Δ = b2-4ac
Δ = -542-4·24·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-54}{2*24}=\frac{0}{48} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+54}{2*24}=\frac{108}{48} =2+1/4 $
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