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6x^2=250
We move all terms to the left:
6x^2-(250)=0
a = 6; b = 0; c = -250;
Δ = b2-4ac
Δ = 02-4·6·(-250)
Δ = 6000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6000}=\sqrt{400*15}=\sqrt{400}*\sqrt{15}=20\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{15}}{2*6}=\frac{0-20\sqrt{15}}{12} =-\frac{20\sqrt{15}}{12} =-\frac{5\sqrt{15}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{15}}{2*6}=\frac{0+20\sqrt{15}}{12} =\frac{20\sqrt{15}}{12} =\frac{5\sqrt{15}}{3} $
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