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6x^2=22x+84
We move all terms to the left:
6x^2-(22x+84)=0
We get rid of parentheses
6x^2-22x-84=0
a = 6; b = -22; c = -84;
Δ = b2-4ac
Δ = -222-4·6·(-84)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-50}{2*6}=\frac{-28}{12} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+50}{2*6}=\frac{72}{12} =6 $
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