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6x^2-19x-7=(2x-7)(3x+1)
We move all terms to the left:
6x^2-19x-7-((2x-7)(3x+1))=0
We multiply parentheses ..
6x^2-((+6x^2+2x-21x-7))-19x-7=0
We calculate terms in parentheses: -((+6x^2+2x-21x-7)), so:We add all the numbers together, and all the variables
(+6x^2+2x-21x-7)
We get rid of parentheses
6x^2+2x-21x-7
We add all the numbers together, and all the variables
6x^2-19x-7
Back to the equation:
-(6x^2-19x-7)
6x^2-19x-(6x^2-19x-7)-7=0
We get rid of parentheses
6x^2-6x^2-19x+19x+7-7=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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