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6x^2+5x-34=0
a = 6; b = 5; c = -34;
Δ = b2-4ac
Δ = 52-4·6·(-34)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-29}{2*6}=\frac{-34}{12} =-2+5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+29}{2*6}=\frac{24}{12} =2 $
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