6x2+3x=4x+2

Solution for 6x2+3x=4x+2 equation:

6x^2+3x=4x+2

We move all terms to the left:

6x^2+3x-(4x+2)=0

We get rid of parentheses

6x^2+3x-4x-2=0

We add all the numbers together, and all the variables

6x^2-1x-2=0

a = 6; b = -1; c = -2;
Δ = b2-4ac
Δ = -12-4·6·(-2)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-7}{2*6}=\frac{-6}{12}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+7}{2*6}=\frac{8}{12}
=2/3
$