6x2+36x=216

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Solution for 6x2+36x=216 equation:



6x^2+36x=216
We move all terms to the left:
6x^2+36x-(216)=0
a = 6; b = 36; c = -216;
Δ = b2-4ac
Δ = 362-4·6·(-216)
Δ = 6480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6480}=\sqrt{1296*5}=\sqrt{1296}*\sqrt{5}=36\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36\sqrt{5}}{2*6}=\frac{-36-36\sqrt{5}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36\sqrt{5}}{2*6}=\frac{-36+36\sqrt{5}}{12} $

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