6x2+1=7x

Solution for 6x2+1=7x equation:

6x^2+1=7x

We move all terms to the left:

6x^2+1-(7x)=0

a = 6; b = -7; c = +1;
Δ = b2-4ac
Δ = -72-4·6·1
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-5}{2*6}=\frac{2}{12}
=1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+5}{2*6}=\frac{12}{12}
=1
$