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6x^2+13x-137=0
a = 6; b = 13; c = -137;
Δ = b2-4ac
Δ = 132-4·6·(-137)
Δ = 3457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{3457}}{2*6}=\frac{-13-\sqrt{3457}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{3457}}{2*6}=\frac{-13+\sqrt{3457}}{12} $
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