6x/2x+25x+4=0

Solution for 6x/2x+25x+4=0 equation:

6x/2x+25x+4=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

25x+6x/2x+4=0

We multiply all the terms by the denominator


25x*2x+6x+4*2x=0

We add all the numbers together, and all the variables

6x+25x*2x+4*2x=0

Wy multiply elements

50x^2+6x+8x=0

We add all the numbers together, and all the variables

50x^2+14x=0

a = 50; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·50·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*50}=\frac{-28}{100}
=-7/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*50}=\frac{0}{100}
=0
$