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6x-8/2x=2
We move all terms to the left:
6x-8/2x-(2)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
6x*2x-2*2x-8=0
Wy multiply elements
12x^2-4x-8=0
a = 12; b = -4; c = -8;
Δ = b2-4ac
Δ = -42-4·12·(-8)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-20}{2*12}=\frac{-16}{24} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+20}{2*12}=\frac{24}{24} =1 $
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