6x-8+2x=4(x+3)-4

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Solution for 6x-8+2x=4(x+3)-4 equation: 



6x-8+2x=4(x+3)-4

We move all terms to the left:

6x-8+2x-(4(x+3)-4)=0

We add all the numbers together, and all the variables

8x-(4(x+3)-4)-8=0



We calculate terms in parentheses: -(4(x+3)-4), so:

4(x+3)-4

We multiply parentheses

4x+12-4

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We get rid of parentheses

8x-4x-8-8=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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