6x-5+3x=9x+27-4x

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Solution for 6x-5+3x=9x+27-4x equation: 



6x-5+3x=9x+27-4x

We move all terms to the left:

6x-5+3x-(9x+27-4x)=0

We add all the numbers together, and all the variables

6x+3x-(5x+27)-5=0

We add all the numbers together, and all the variables

9x-(5x+27)-5=0

We get rid of parentheses

9x-5x-27-5=0

We add all the numbers together, and all the variables

4x-32=0

We move all terms containing x to the left, all other terms to the right

4x=32

x=32/4

x=8

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