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6x-4=x(x+5)
We move all terms to the left:
6x-4-(x(x+5))=0
We calculate terms in parentheses: -(x(x+5)), so:We get rid of parentheses
x(x+5)
We multiply parentheses
x^2+5x
Back to the equation:
-(x^2+5x)
-x^2+6x-5x-4=0
We add all the numbers together, and all the variables
-1x^2+x-4=0
a = -1; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·(-1)·(-4)
Δ = -15
Delta is less than zero, so there is no solution for the equation
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