6x-4(3x-19)=16

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Solution for 6x-4(3x-19)=16 equation: 



6x-4(3x-19)=16

We move all terms to the left:

6x-4(3x-19)-(16)=0

We multiply parentheses

6x-12x+76-16=0

We add all the numbers together, and all the variables

-6x+60=0

We move all terms containing x to the left, all other terms to the right

-6x=-60

x=-60/-6

x=+10

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