6x-4(3-2x)=4(x-4)-36

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Solution for 6x-4(3-2x)=4(x-4)-36 equation:



6x-4(3-2x)=4(x-4)-36
We move all terms to the left:
6x-4(3-2x)-(4(x-4)-36)=0
We add all the numbers together, and all the variables
6x-4(-2x+3)-(4(x-4)-36)=0
We multiply parentheses
6x+8x-(4(x-4)-36)-12=0
We calculate terms in parentheses: -(4(x-4)-36), so:
4(x-4)-36
We multiply parentheses
4x-16-36
We add all the numbers together, and all the variables
4x-52
Back to the equation:
-(4x-52)
We add all the numbers together, and all the variables
14x-(4x-52)-12=0
We get rid of parentheses
14x-4x+52-12=0
We add all the numbers together, and all the variables
10x+40=0
We move all terms containing x to the left, all other terms to the right
10x=-40
x=-40/10
x=-4

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