6x-4(3-2x)=4(x-4)-36

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Solution for 6x-4(3-2x)=4(x-4)-36 equation: 



6x-4(3-2x)=4(x-4)-36

We move all terms to the left:

6x-4(3-2x)-(4(x-4)-36)=0

We add all the numbers together, and all the variables

6x-4(-2x+3)-(4(x-4)-36)=0

We multiply parentheses

6x+8x-(4(x-4)-36)-12=0



We calculate terms in parentheses: -(4(x-4)-36), so:

4(x-4)-36

We multiply parentheses

4x-16-36

We add all the numbers together, and all the variables

4x-52

Back to the equation:

-(4x-52)



We add all the numbers together, and all the variables

14x-(4x-52)-12=0

We get rid of parentheses

14x-4x+52-12=0

We add all the numbers together, and all the variables

10x+40=0

We move all terms containing x to the left, all other terms to the right

10x=-40

x=-40/10

x=-4

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