6x-3(x-9)=13+4(x-2)

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Solution for 6x-3(x-9)=13+4(x-2) equation: 



6x-3(x-9)=13+4(x-2)

We move all terms to the left:

6x-3(x-9)-(13+4(x-2))=0

We multiply parentheses

6x-3x-(13+4(x-2))+27=0



We calculate terms in parentheses: -(13+4(x-2)), so:

13+4(x-2)

determiningTheFunctionDomain
4(x-2)+13

We multiply parentheses

4x-8+13

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We add all the numbers together, and all the variables

3x-(4x+5)+27=0

We get rid of parentheses

3x-4x-5+27=0

We add all the numbers together, and all the variables

-1x+22=0

We move all terms containing x to the left, all other terms to the right

-x=-22

x=-22/-1

x=+22

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