6x-3(x+4)=3(2x+1)

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Solution for 6x-3(x+4)=3(2x+1) equation: 



6x-3(x+4)=3(2x+1)

We move all terms to the left:

6x-3(x+4)-(3(2x+1))=0

We multiply parentheses

6x-3x-(3(2x+1))-12=0



We calculate terms in parentheses: -(3(2x+1)), so:

3(2x+1)

We multiply parentheses

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

3x-(6x+3)-12=0

We get rid of parentheses

3x-6x-3-12=0

We add all the numbers together, and all the variables

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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