6x-3(x+1)=3-4(x+2)

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Solution for 6x-3(x+1)=3-4(x+2) equation: 



6x-3(x+1)=3-4(x+2)

We move all terms to the left:

6x-3(x+1)-(3-4(x+2))=0

We multiply parentheses

6x-3x-(3-4(x+2))-3=0



We calculate terms in parentheses: -(3-4(x+2)), so:

3-4(x+2)

determiningTheFunctionDomain
-4(x+2)+3

We multiply parentheses

-4x-8+3

We add all the numbers together, and all the variables

-4x-5

Back to the equation:

-(-4x-5)



We add all the numbers together, and all the variables

3x-(-4x-5)-3=0

We get rid of parentheses

3x+4x+5-3=0

We add all the numbers together, and all the variables

7x+2=0

We move all terms containing x to the left, all other terms to the right

7x=-2

x=-2/7

x=-2/7

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