6x-3(1+5x)=-8(x-4)+4

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Solution for 6x-3(1+5x)=-8(x-4)+4 equation: 



6x-3(1+5x)=-8(x-4)+4

We move all terms to the left:

6x-3(1+5x)-(-8(x-4)+4)=0

We add all the numbers together, and all the variables

6x-3(5x+1)-(-8(x-4)+4)=0

We multiply parentheses

6x-15x-(-8(x-4)+4)-3=0



We calculate terms in parentheses: -(-8(x-4)+4), so:

-8(x-4)+4

We multiply parentheses

-8x+32+4

We add all the numbers together, and all the variables

-8x+36

Back to the equation:

-(-8x+36)



We add all the numbers together, and all the variables

-9x-(-8x+36)-3=0

We get rid of parentheses

-9x+8x-36-3=0

We add all the numbers together, and all the variables

-1x-39=0

We move all terms containing x to the left, all other terms to the right

-x=39

x=39/-1

x=-39

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