6x-2-3(x-4)=12

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Solution for 6x-2-3(x-4)=12 equation: 



6x-2-3(x-4)=12

We move all terms to the left:

6x-2-3(x-4)-(12)=0

We add all the numbers together, and all the variables

6x-3(x-4)-14=0

We multiply parentheses

6x-3x+12-14=0

We add all the numbers together, and all the variables

3x-2=0

We move all terms containing x to the left, all other terms to the right

3x=2

x=2/3

x=2/3

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