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6x-2(x-5)=3(3x-10)
We move all terms to the left:
6x-2(x-5)-(3(3x-10))=0
We multiply parentheses
6x-2x-(3(3x-10))+10=0
We calculate terms in parentheses: -(3(3x-10)), so:We add all the numbers together, and all the variables
3(3x-10)
We multiply parentheses
9x-30
Back to the equation:
-(9x-30)
4x-(9x-30)+10=0
We get rid of parentheses
4x-9x+30+10=0
We add all the numbers together, and all the variables
-5x+40=0
We move all terms containing x to the left, all other terms to the right
-5x=-40
x=-40/-5
x=+8
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