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6x-2(x-3)=5x-(3x+2)
We move all terms to the left:
6x-2(x-3)-(5x-(3x+2))=0
We multiply parentheses
6x-2x-(5x-(3x+2))+6=0
We calculate terms in parentheses: -(5x-(3x+2)), so:We add all the numbers together, and all the variables
5x-(3x+2)
We get rid of parentheses
5x-3x-2
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
4x-(2x-2)+6=0
We get rid of parentheses
4x-2x+2+6=0
We add all the numbers together, and all the variables
2x+8=0
We move all terms containing x to the left, all other terms to the right
2x=-8
x=-8/2
x=-4
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