6x-2(x-3)=4(x+1)+8

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Solution for 6x-2(x-3)=4(x+1)+8 equation:


Simplifying
6x + -2(x + -3) = 4(x + 1) + 8

Reorder the terms:
6x + -2(-3 + x) = 4(x + 1) + 8
6x + (-3 * -2 + x * -2) = 4(x + 1) + 8
6x + (6 + -2x) = 4(x + 1) + 8

Reorder the terms:
6 + 6x + -2x = 4(x + 1) + 8

Combine like terms: 6x + -2x = 4x
6 + 4x = 4(x + 1) + 8

Reorder the terms:
6 + 4x = 4(1 + x) + 8
6 + 4x = (1 * 4 + x * 4) + 8
6 + 4x = (4 + 4x) + 8

Reorder the terms:
6 + 4x = 4 + 8 + 4x

Combine like terms: 4 + 8 = 12
6 + 4x = 12 + 4x

Add '-4x' to each side of the equation.
6 + 4x + -4x = 12 + 4x + -4x

Combine like terms: 4x + -4x = 0
6 + 0 = 12 + 4x + -4x
6 = 12 + 4x + -4x

Combine like terms: 4x + -4x = 0
6 = 12 + 0
6 = 12

Solving
6 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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