6x-2(6-5x)+3x=10-4(2-x)

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Solution for 6x-2(6-5x)+3x=10-4(2-x) equation: 



6x-2(6-5x)+3x=10-4(2-x)

We move all terms to the left:

6x-2(6-5x)+3x-(10-4(2-x))=0

We add all the numbers together, and all the variables

6x-2(-5x+6)+3x-(10-4(-1x+2))=0

We add all the numbers together, and all the variables

9x-2(-5x+6)-(10-4(-1x+2))=0

We multiply parentheses

9x+10x-(10-4(-1x+2))-12=0



We calculate terms in parentheses: -(10-4(-1x+2)), so:

10-4(-1x+2)

determiningTheFunctionDomain
-4(-1x+2)+10

We multiply parentheses

4x-8+10

We add all the numbers together, and all the variables

4x+2

Back to the equation:

-(4x+2)



We add all the numbers together, and all the variables

19x-(4x+2)-12=0

We get rid of parentheses

19x-4x-2-12=0

We add all the numbers together, and all the variables

15x-14=0

We move all terms containing x to the left, all other terms to the right

15x=14

x=14/15

x=14/15

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