6x-2(2x-3)=(x+1)+4

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Solution for 6x-2(2x-3)=(x+1)+4 equation: 



6x-2(2x-3)=(x+1)+4

We move all terms to the left:

6x-2(2x-3)-((x+1)+4)=0

We multiply parentheses

6x-4x-((x+1)+4)+6=0



We calculate terms in parentheses: -((x+1)+4), so:

(x+1)+4

We get rid of parentheses

x+1+4

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)



We add all the numbers together, and all the variables

2x-(x+5)+6=0

We get rid of parentheses

2x-x-5+6=0

We add all the numbers together, and all the variables

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1

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