6x-2(2x+3)=-10(x-3)

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Solution for 6x-2(2x+3)=-10(x-3) equation: 



6x-2(2x+3)=-10(x-3)

We move all terms to the left:

6x-2(2x+3)-(-10(x-3))=0

We multiply parentheses

6x-4x-(-10(x-3))-6=0



We calculate terms in parentheses: -(-10(x-3)), so:

-10(x-3)

We multiply parentheses

-10x+30

Back to the equation:

-(-10x+30)



We add all the numbers together, and all the variables

2x-(-10x+30)-6=0

We get rid of parentheses

2x+10x-30-6=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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