6x-1=3(x-4)+7

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Solution for 6x-1=3(x-4)+7 equation: 



6x-1=3(x-4)+7

We move all terms to the left:

6x-1-(3(x-4)+7)=0



We calculate terms in parentheses: -(3(x-4)+7), so:

3(x-4)+7

We multiply parentheses

3x-12+7

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We get rid of parentheses

6x-3x+5-1=0

We add all the numbers together, and all the variables

3x+4=0

We move all terms containing x to the left, all other terms to the right

3x=-4

x=-4/3

x=-1+1/3

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