6x-11x+8(-2x-4)+2(x+2)=-4(3x+3)

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Solution for 6x-11x+8(-2x-4)+2(x+2)=-4(3x+3) equation: 



6x-11x+8(-2x-4)+2(x+2)=-4(3x+3)

We move all terms to the left:

6x-11x+8(-2x-4)+2(x+2)-(-4(3x+3))=0

We add all the numbers together, and all the variables

-5x+8(-2x-4)+2(x+2)-(-4(3x+3))=0

We multiply parentheses

-5x-16x+2x-(-4(3x+3))-32+4=0



We calculate terms in parentheses: -(-4(3x+3)), so:

-4(3x+3)

We multiply parentheses

-12x-12

Back to the equation:

-(-12x-12)



We add all the numbers together, and all the variables

-19x-(-12x-12)-28=0

We get rid of parentheses

-19x+12x+12-28=0

We add all the numbers together, and all the variables

-7x-16=0

We move all terms containing x to the left, all other terms to the right

-7x=16

x=16/-7

x=-2+2/7

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