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6x-11=17/2x
We move all terms to the left:
6x-11-(17/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6x-(+17/2x)-11=0
We get rid of parentheses
6x-17/2x-11=0
We multiply all the terms by the denominator
6x*2x-11*2x-17=0
Wy multiply elements
12x^2-22x-17=0
a = 12; b = -22; c = -17;
Δ = b2-4ac
Δ = -222-4·12·(-17)
Δ = 1300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1300}=\sqrt{100*13}=\sqrt{100}*\sqrt{13}=10\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-10\sqrt{13}}{2*12}=\frac{22-10\sqrt{13}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+10\sqrt{13}}{2*12}=\frac{22+10\sqrt{13}}{24} $
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