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6x-10-x-(2x-3)=1-(2x-5)
We move all terms to the left:
6x-10-x-(2x-3)-(1-(2x-5))=0
We add all the numbers together, and all the variables
5x-(2x-3)-(1-(2x-5))-10=0
We get rid of parentheses
5x-2x-(1-(2x-5))+3-10=0
We calculate terms in parentheses: -(1-(2x-5)), so:We add all the numbers together, and all the variables
1-(2x-5)
determiningTheFunctionDomain -(2x-5)+1
We get rid of parentheses
-2x+5+1
We add all the numbers together, and all the variables
-2x+6
Back to the equation:
-(-2x+6)
3x-(-2x+6)-7=0
We get rid of parentheses
3x+2x-6-7=0
We add all the numbers together, and all the variables
5x-13=0
We move all terms containing x to the left, all other terms to the right
5x=13
x=13/5
x=2+3/5
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